4x^2-33x^2+50=0

Solution for 4x^2-33x^2+50=0 equation:

4x^2-33x^2+50=0

We add all the numbers together, and all the variables

-29x^2+50=0

a = -29; b = 0; c = +50;
Δ = b2-4ac
Δ = 02-4·(-29)·50
Δ = 5800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5800}=\sqrt{100*58}=\sqrt{100}*\sqrt{58}=10\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{58}}{2*-29}=\frac{0-10\sqrt{58}}{-58}
=-\frac{10\sqrt{58}}{-58}
=-\frac{5\sqrt{58}}{-29}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{58}}{2*-29}=\frac{0+10\sqrt{58}}{-58}
=\frac{10\sqrt{58}}{-58}
=\frac{5\sqrt{58}}{-29}
$